min(double a, double b)

Method min(double a, double b)

Return type: double

Examples of how the element is used (one line per example):
[add your own example]

1	percent = Math.min((currentValue+1)/(double)finalValue, 1.0);
2	double ratio = Math.min(Math.min(xRatio, yRatio), 1.0);
3	n.x += Math.max(-5, Math.min(5, n.dx));
4	minElapsed = (long) Math.min(MAX_INTERVAL, Math.max(MIN_LAMBDA * ONE_DAY / pilferRate, MIN_INTERVAL));
5	Xmi[i] = Math.min(XY[i], Xmin[i]);
6	return new Double(Math.min(d1.doubleValue(), d2.doubleValue()));
7	pilferage = Math.min(pilferage, theInventoryReport.theQuantity);
8	endPointX = Math.min (line.getX2 (), (bounds.x+bounds.width)-MIN_WIDTH);
9	time = Math.min(maxTime, scheduler.nextEventTime());
10	Math.max ( Math.min ( x_scale, y_scale ), ovalSizeMin );
11	double k = Math.min(xk,yk);
12	(Math.max(0.0d, Math.min((double) m_width, clip.xMin)),
13	double w = Math.min(tileWidth, tiledWidth);
14	ymin = Math.min(ymin, a[0]);
15	min = Math.min(min, d1);
16	double scale = Math.min(pf.getImageableWidth() / d.width,
17	scale = Math.min(pageWidth / (double)(drawingArea.width + 1), pageHeight / (double)(drawingArea.height + 1));
18	curRate = Math.min(MAX_RATE, curRate);
19	Math.min(picHeight / s.width, picWidth / s.height):

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